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1. Study the following table which shows the amount of money invested (Rupees in crore) in the core infrastructure areas of two districts. A and B of a State, and answer the below five questions.
If the total investment in district B shows the same rate of increase in 1997, as it had shown from 1995 to 1996, what approximately would be the total investment in B in 1997?
= 8352 - 7081.6
= 1270.4
Increase % = × 100
= 17.9% (Approx)
B investment in 1997
= × 8352
= Rs. 9850 crore (Approx)
District A | District B | |||
Core Area | 1995 | 1996 | 1995 | 1996 |
Electricity Chemical Thermal Solar Nuclear | 815.2 389.5 632.4 468.1 617.9 | 1054.2 476.7 565.9 589.6 803.1 | 2065.8 745.3 1232.7 1363.5 1674.3 | 2365.1 986.4 1026.3 1792.1 2182.1 |
Total | 2923.1 | 3489.5 | 7081.6 | 8352.0 |
If the total investment in district B shows the same rate of increase in 1997, as it had shown from 1995 to 1996, what approximately would be the total investment in B in 1997?
Solution:
Difference of 1995 & 1996= 8352 - 7081.6
= 1270.4
Increase % = × 100
= 17.9% (Approx)
B investment in 1997
= × 8352
= Rs. 9850 crore (Approx)