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1. 50 men took a dip in a water tank 40 m long and 20 m broad on a religious day. If the average displacement of water by a man is 4 m³, then the rise in the water level in the tank will be:

A. 20 cm

B. 25 cm

C. 35 cm

D. 50 cm

Solution:

\begin{aligned} Total Volume of water displaced \\ = (4 \times 50) m^{3} = 200 m^{3} \\ ∴ Rise in water level \\ = (\frac{200}{40 \times 20}) m \\ = 0.25 m \\ = 25 c m \end{aligned}

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