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1. 60 kg of an alloy A is mixed with 100 kg of alloy B. If alloy A has lead and tin in the ratio 3 : 2 and alloy B has tin and copper in the ratio 1 : 4, the amount of tin in the new alloy is -

A. 44 kg

B. 53 kg

C. 80 kg

D. 24 kg

Solution:

Quantity of tin in 60 kg of A

\begin{aligned} = (60 \times \frac{2}{5}) kg \\ = 24 kg \end{aligned}

Quantity of tin in 100 kg of B

\begin{aligned} = (100 \times \frac{1}{5}) kg \\ = 20 kg \end{aligned}

∴ Quantity of tin in the new alloy
= (24 + 20) kg
= 44 kg

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