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1. A 280 meter long train crosses a platform thrice its length in 50 seconds. What is the speed of the train in km/hr?

A. 60.48

B. 64.86

C. 80.64

D. 82.38

Solution:

\begin{aligned} Length of train \\ =  280 m \\ Length of platform \\ =  (3 \times 280) m  =  840m \\ ∴ Speed of train \\ = (\frac{280 + 840}{50}) m / \sec \\ = \frac{1120}{50} m / \sec \\ = (\frac{1120}{50} \times \frac{18}{5}) k m / h r \\ = 80.64 k m / h r \end{aligned}

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