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1. A and B are two alloys in which ratios of gold and copper are 5 : 3 and 5 : 11 respectively. If these equally amount of two alloys are melted and made alloy C. What will be the ratio of gold and copper in alloy C?

A. 25 : 23

B. 33 : 25

C. 15 : 17

D. 17 : 15

Solution:

Ratio of Gold and Copper in Alloy A = 5 : 3
Ratio of Gold and Copper in Alloy B = 5 : 11
Amount of Gold in Alloy A =

\frac{5}{8}

Amount of Gold In Alloy B =

\frac{5}{16}

Amount of Copper in A =

\frac{3}{8}

Amount of Copper in B =

\frac{11}{16}

Amount of Gold In C,
= (Amount of gold in A + Amount of gold in B) =

\frac{5}{8}

\frac{5}{16}

\frac{10 + 5}{16}

\frac{15}{16}

Amount of Copper in C,
= Amount of Copper in A + Amount of Copper in B =

\frac{3}{8}

\frac{11}{16}

\frac{17}{16}

So,
Ratio of Gold and Copper in C,

= \frac{15}{16} : \frac{17}{16} = 15 : 17

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