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1. A and B are two alloys of gold and copper prepared by mixing metals in the ratio 5 : 3 and 5 : 11 respectively. Equal quantities of these alloys are melted to form a third alloys C. The ratio of gold and copper in the alloy C is -

A. 25 : 13

B. 33 : 15

C. 15 : 17

D. 17 : 15

Solution:

According to the question,

\begin{matrix} Alloy A \to 5 \times_{2} : 3 \times_{2} = 8 \times_{2} \\ Alloy B \to 5 : 11 = 16 \end{matrix}]

Equal quantity are mixed

\begin{aligned} Alloy A \to 10 : 6 = 16 \\ Alloy B \to 5 : 11 = 16 \\ Alloy C \to 15 : 17 \end{aligned}

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