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1. A and B completed a work together in 5 days. had A worked at twice the speed and B at half the speed, it would have taken them four days to complete the job. How much time would it take for A alone to do the work?

Solution:
Assume work to be done 100%.
First case,
A + B = 1005 = 20% work done per day -------- (1)
Second case,
2A + B2 = 1004 = 25% work done per day ------ (2)
On solving equation (1) and (2), we get
A = 10 days

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