Practice | Hashtable

Home > Practice > Arithmetic Aptitude > Probability > Miscellaneous

1. A box contains 4 red, 5 green and 6 white balls. A ball is drawn at random from the box. What is the probability that the ball drawn is either red or green ?

A. $\frac{2}{5}$

B. $\frac{3}{5}$

C. $\frac{1}{5}$

D. $\frac{7}{15}$

Solution:

Total number of balls = (4 + 5 + 6) = 15
P (drawing a red ball or a green ball) = P (red) + P (green)

\begin{aligned} = (\frac{4}{15} + \frac{5}{15}) \\ = \frac{9}{15} \\ = \frac{3}{5} \end{aligned}

You must login to add comments. Login now.