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1. A car traveled first 36 km at 6 km/h faster than the usual speed, but it returned the same distance at 6 km/h slower than usual speed. I the total time taken by car is 8 hours, for how many hours does it traveled at the faster speed ?

Solution:
Let the original speed be S then,
Total time taken,
36S−6+36S+6    = 8 hours
On solving the equation, we get
S = 12, -3
Then possible value of S = 12 km/h.
Thus, time taken by car at faster speed = 3612+6  = 2 hours

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