Practice | Hashtable

1. A cistern 6m long and 4 m wide contains water up to a depth of 1 m 25 cm. The total area of the wet surface is:

A. 49 m²

B. 50 m²

C. 53.5 m²

D. 55 m²

Solution:

\begin{aligned} Area of the wet surface \\ = [2 (l b + b h + l h) - l b] \\ = 2 (b h + l h) + l b \\ = [2 (4 \times 1.25 + 6 \times 1.25) + 6 \times 4] m^{2} \\ = 49 m^{2} \end{aligned}

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