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1. A complete $\frac{7}{10}$ of a work in 15 days, then he completed the remaining work with the help of B in 4 days. In how many day A and B can complete entire work together?

A. $10 \frac{1}{2} days$

B. $12 \frac{2}{3} days$

C. $13 \frac{1}{3} days$

D. $8 \frac{1}{4} days$

Solution:

\frac{7}{10}

part of work has been completed by A in 15 days. Then,
Rest work = 1 -

\frac{7}{10}

\frac{3}{10}

part
Given, That

\frac{3}{10}

part of the work is completed by A and B together in 4 days. Means,
(A + B) completed the

\frac{3}{10}

of work in 4 days
So, (A + B)'s 1 day's work =

\frac{3}{10 \times 4}

\frac{3}{40}

Hence,
(A + B) can complete the work in

\frac{40}{3}

13 \frac{1}{3}

days

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