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1. A has 50 coins of 10 paise denominations. While B has 10 coins of 50 paise denominations. C has 20 coins of 25 paise denominations while D has 25 coins of 20 paise denominations. The average number of paise per person is :

A. 450 paise

B. 500 paise

C. 550 paise

D. 650 paise

Solution:

\begin{aligned} \frac{[(10 \times 50) + (50 \times 10) + (20 \times 25) + (25 \times 20)]}{4} \\ = 500 paise \end{aligned}

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