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1. A hemispherical bowl of internal radius 12 cm contains liquid. This liquid is to be filled into cylindrical container of diameter 4 cm and height 3 cm. The number of containers that is necessary to empty the bowl is :

A. 80

B. 96

C. 100

D. 112

Solution:

Volume of hemispherical bowl :

= (\frac{2}{3} \times π \times 12 \times 12 \times 12) c m^{3}

Volume of 1 cylindrical container :

= (π \times 2 \times 2 \times 3) c m^{3}

∴ Number of containers required :

\begin{aligned} = \frac{2}{3} \times \frac{12 \times 12 \times 12}{2 \times 2 \times 3} \\ = 96 \end{aligned}

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