Practice | Hashtable

Home > Practice > Arithmetic Aptitude > Alligation or Mixture > Miscellaneous

1. A lump of two metals weighing 18 g is worth Rs. 87 but if their weight is interchanged, it would be worth Rs. 78.60. If the price of one metal be Rs. 6.70 per gram, find the weight of the other metal in the mixture.

A. 8g

B. 12g

C. 15g

D. 18g

Solution:

Cost of (18g of 1^st metal + 18g of 2^nd metal) = Rs. 165.60
Cost of (1g of 1^st metal + 1g metal of 2^nd metal) = Rs. 9.20
Hence cost of 1g of 2^nd metal,
= 9.20 - 6.70
= Rs. 2.5
Mean price = Rs.

\frac{87}{18}

Now,

\frac{quantity of 1^{st} metal}{quantity of 2^{nd} metal}

=

\frac{14}{6} : \frac{56}{30} = 5 : 4

Quantity of 2^nd metal =

\frac{18 \times 4}{9}

= 8g

You must login to add comments. Login now.