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1. A man bought a horse and a cart. If he sold the horse at 10 % loss and the cart at 20 % gain, he would not lose anything; but if he sold the horse at 5% loss and the cart at 5% gain, he would lose Rs. 10 in the bargain. The amount paid by him was Rs._______ for the horse and Rs.________ for the cart.
10% of loss in selling horse = 20% of gain in selling the cart.
Therefore, = (20 × 100) × Y
Or, X = 2y --------------(1)
5% of loss in selling horse is 10 more than the 5% gain in selling the cart.
Therefore,
=> 5X – 1000 = 5Y
Using equation (1),
=> 10Y – 1000 = 5Y
=> 5Y = 1000
=> Y =200
=> X = 400
CP of Horse = Rs. 400
CP of the Cart = Rs. 200
Solution:
Let X be the cost of horse and Y be the cost of the cart.10% of loss in selling horse = 20% of gain in selling the cart.
Therefore, = (20 × 100) × Y
Or, X = 2y --------------(1)
5% of loss in selling horse is 10 more than the 5% gain in selling the cart.
Therefore,
=> 5X – 1000 = 5Y
Using equation (1),
=> 10Y – 1000 = 5Y
=> 5Y = 1000
=> Y =200
=> X = 400
CP of Horse = Rs. 400
CP of the Cart = Rs. 200