Home > Practice > Arithmetic Aptitude > Time and Distance > Miscellaneous
1. A man reduces his speed from 20 kmph to 18 kmph. So, he takes 10 minutes more than the normal time. what is the distance traveled by him.
Thus,
Distance traveled = Speed × time = = 30 km.
Alternatively,
As the speed decreases from 20 kmph to 18 kmph i.e. 10 % increment in usual time.
10% = 10 min
100% = 100 min.
Now,
Distance traveled by him,
=
= 30 km.
Solution:
Usual time = 9 × 10 = 90 min = hThus,
Distance traveled = Speed × time = = 30 km.
Alternatively,
As the speed decreases from 20 kmph to 18 kmph i.e. 10 % increment in usual time.
10% = 10 min
100% = 100 min.
Now,
Distance traveled by him,
=
= 30 km.