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1. A man sells chocolates which are in the boxes. Only either full box or half a box of chocolates can be purchased from him. A customer comes and buys half the number of boxes which the seller had plus half box more. A second customer comes and purchases half the remaining number of boxes plus half a box. After this the seller is left with no chocolate boxes. How many chocolate boxes the seller had initially?

A. 2

B. 3

C. 4

D. 3.5

Solution:

The best way to go through the options
Let there are initially 3 boxes then,
1^st customer gets =

\frac{3}{2}

\frac{1}{2}

= 2
Remaining boxes = 3 - 2 = 1
2^nd customer =

\frac{1}{2}

\frac{1}{2}

= 1
So, option B is correct.

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