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1. A milk vendor has 2 cans of milk. The first contains 25% water and the rest milk. The second contains 50% water. How much milk should he mix from each of the containers so as to get 12 litres of milk such that the ratio of water to milk is 3 : 5?

A. 4 litres, 8 litres

B. 6 litres, 6 litres

C. 5 litres, 7 litres

D. 7 litres, 5 litres

Solution:

Let the cost of 1 litre milk be Rs. 1
Milk in 1 litre mixture in 1^st can =

\frac{3}{4}

litre, C.P. of 1 litre mixture in 1^st can Rs.

\frac{3}{4}

Milk in 1 litre mixture in 2^nd can =

\frac{1}{2}

litre, C.P. of 1 litre mixture in 2^nd can Rs.

\frac{1}{2}

Milk in 1 litre of final mixture =

\frac{5}{8}

litre, Mean price = Rs.

\frac{5}{8}

By the rule of alligation, we have:
Alligation mcq solution image

∴ Ratio of two mixtures =

\frac{1}{8}

\frac{1}{8}

= 1 : 1
So, quantity of mixture taken from each can =

(\frac{1}{2} \times 12)

= 6 litres

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