Practice | Hashtable

Home > Practice > Arithmetic Aptitude > Probability > Miscellaneous

1. A number X is chosen at random from the numbers -3, -2, -1, 0, 1, 2, 3. What is the probability that $| X | < 2$

A. $\frac{5}{7}$

B. $\frac{3}{7}$

C. $\frac{3}{5}$

D. $\frac{1}{3}$

Solution:

| X |

can take 7 values.
To get

| X | < 2

(i.e., -2 < x < + 2) take X = {-1, 0, 1}

P (| X | < 2) =

\frac{Favourable Cases}{Total Cases}

= \frac{3}{7}

You must login to add comments. Login now.