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1. A string of length 221 metre is cut into two parts such that one part is $\frac{9}{4}$ th as long as the rest of the string, then the difference between the larger piece and the shorter piece is :

A. 58 m

B. 53 m

C. 85 m

D. 76 m

Solution:

Let one part of string is x.
Now,
x +

\frac{9 x}{4}

= 221 m
x = 68 meter
and,

\frac{9 x}{4}

= 153 m
Difference between two parts = 153 - 68 = 85m.

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