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1. A student was asked to divide the half of a certain number by 6 and the other half by 4 and then to add the two quantities so obtained. Instead of doing so the student divided the number by 5 and the result fell short by 4. The given number was ?

Solution:
Let the number be x
Then,
[(x2)6+(x2)4]x5=4x12+x8x5=410x+15x24x120=4x=4×120x=480

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