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1. A train met with an accident 120 km from station A. It completed the remaining journey at $\frac{5}{6}$ of its previous speed and reached 2 hour late at station B. Had the accident taken place 300 km further, it would have been only 1 hour late. What is the speed of the train?

A. 100 km/h

B. 12 km/h

C. 60 km/h

D. 50 km/h

Solution:

A ____100 km____ P₁ ________300 km_____ P₂ ____X______ B

If speed becomes

\frac{5}{6}

then time taken will be

\frac{6}{5}

of original time.
Thus, extra time = 2 hour

\frac{1}{5}

= 2 hour
Thus unusual time which is require to complete the journey = 5 × 2 = 10 hours.
It means It covers 300 km distance in 5 hours.
then speed =

\frac{300}{5}

= 60 km/h

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