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1. A train moving at a rate of 36 km/hr crosses a standing man in 10 seconds. It will cross a platform 55 meters long in?

A. 6 second

B. 7 second

C. $15 \frac{1}{2}$ second

D. $5 \frac{1}{2}$ second

Solution:

\begin{aligned} Length of the train \\ =  Speed \times time \\ =  36 km/hr \times 10 sec \\ =  36 \times \frac{5}{18} m/s \times 10 \sec \\ = 100 metres \\ Therefore, \\ Time taken by train to cross a plateform \\ of 55 metre long in time \\ = \frac{(100 + 55)}{36 \times \frac{5}{18}} \\ = \frac{155}{10} \\ Time = 15 \frac{1}{2} \sec \end{aligned}

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