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1. B is twice as old as A but twice younger than F. C is half the age of A but is twice older than D. Who is the second oldest ?
Then, B = 2x
and, F = 4x
C = x/2
and D = x/4
Thus, The second oldest is B.
Solution:
Let, A = xThen, B = 2x
and, F = 4x
C = x/2
and D = x/4
Thus, The second oldest is B.