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1. December 9, 2001 is Sunday. What was the day on December 9, 1971?
We know leap year has 2 odd days
Here, Number of Normal years= 22 and number of Leap years =8
So odd days =22+16 =38 i.e 3 odd days (remainder when 38 is divided by 7,i.e. 3)
Hence, it was a Thursday.
Solution:
We know every year has 1 odd daysWe know leap year has 2 odd days
Here, Number of Normal years= 22 and number of Leap years =8
So odd days =22+16 =38 i.e 3 odd days (remainder when 38 is divided by 7,i.e. 3)
Hence, it was a Thursday.