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1. Dev can hit a target 3 times in 6 shots pawan can hit the target 2 times in 6 shots and Lakhan can hit the target 4 times in 4 shots. What is the probability that at least 2 shots hit the target -

A. $\frac{2}{3}$

B. $\frac{1}{3}$

C. $\frac{1}{2}$

D. None of these

Solution:

Probability of hitting the target:
Dev can hit target ⇒

\frac{3}{6}

\frac{1}{2}

Lakhan can hit target =

\frac{4}{4}

= 1
Pawan can hit target =

\frac{2}{6}

\frac{1}{3}

Required probability that at least 2 shorts hit target

\begin{aligned} = \frac{1}{2} \times \frac{2}{3} + \frac{1}{2} \times \frac{1}{3} + \frac{1}{2} \times \frac{1}{3} \\ = \frac{1}{3} + \frac{1}{6} + \frac{1}{6} \\ = \frac{4}{6} \\ = \frac{2}{3} \end{aligned}

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