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1. Farah got married 8 years ago, Today her age is $1 \frac{2}{7}$ times her age at the time of her marriage. At present her daughter's age is one-sixth of her age. What was her daughter's age 3 years ago ?

A. 4 Years

B. 3 Years

C. 6 Years

D. Cannot be determind

Solution:

Let Farah's age 8 years ago be x years.
Then , her present age = (x + 8)

\begin{aligned} ∴ x + 8 = \frac{9}{7} x \\ \Rightarrow 7 x + 56 = 9 x \\ \Rightarrow 2 x = 56 \\ \Rightarrow x = 28 \end{aligned}

∴ Farah's age now
= (x + 8) years
= (28 + 8) years
= 36
Her daughter's age now
=

(\frac{1}{6} \times 36)

years
= 6 years
Her daughter's age 3 years ago
= (6 - 3) years
= 3 years

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