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1. Find a positive number which when increased by 17 is equal to 60 times the reciprocal of the number.

A. 3

B. 10

C. 17

D. 20

Solution:

\begin{aligned} Let the number be x \\ Then, x + 17 = \frac{60}{x} \\ \Rightarrow x^{2} + 17 x - 60 = 0 \\ \Rightarrow (x + 20) (x - 3) = 0 \\ \Rightarrow x = 3 \end{aligned}

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