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1. Find the value of x in the expression : $\sqrt[4]{3 x + 1} = 2$

A. 3

B. 6

C. 4

D. 5

Solution:

\begin{aligned} \sqrt[4]{3 x + 1} = 2 \\ \Rightarrow {(\sqrt[4]{3 x + 1})}^{4} = 2^{4} \\ \Rightarrow {(3 x + 1)}^{4 \times \frac{1}{4}} = 16 \\ \Rightarrow 3 x = 15 \\ \Rightarrow x = 5 \end{aligned}

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