Practice | Hashtable

Home > Practice > Arithmetic Aptitude > Surds and Indices > Miscellaneous

1. Given that 10^0.48 = x, 10^0.70 = y and x^z = y², then the value of z is close to:

A. 1.45

B. 1.88

C. 2.9

D. 3.7

Solution:

\begin{aligned} x^{z} = y^{2} \Leftrightarrow 10^{(0.48 z)} = 10^{2 \times 0.70} = 10^{1.40} \\ \Rightarrow 0.48 z = 1.40 \\ \Rightarrow z = \frac{140}{48} = \frac{35}{12} = 2.9 (approx) \end{aligned}

You must login to add comments. Login now.