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1. If A travels to his school from his house at the speed of 3 km/h, then he reaches the school 5 minutes late. If he travels at the speed of 4 km/h, he reaches the school 5 minutes earlier than school time. The distance of his school from his house is:

A. 1 km

B. 2 km

C. 3 km

D. 4 km

Solution:

Let the distance between school and home be x km.
The difference of time when A goes school to school with these two different speed is 10 min

\begin{aligned} = \frac{10}{60} hour \\ Now, \\ \frac{x}{3} - \frac{x}{4} = \frac{10}{60} \\ Or, \frac{x}{12} = \frac{1}{6} \\ Or, x = \frac{12}{6} \\ = 2 km \end{aligned}

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