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1. if $2^{x} = \sqrt[3]{32}$ then x is equal to = ?

A. 5

B. 3

C. $\frac{3}{5}$

D. $\frac{5}{3}$

Solution:

\begin{aligned} 2^{x} = \sqrt[3]{32} \\ \Rightarrow 2^{x} = {(32)}^{\frac{1}{3}} = {(2^{5})}^{\frac{1}{3}} \\ \Rightarrow x = \frac{5}{3} \end{aligned}

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