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1. In a simultaneous throw of two dice, what is the probability of getting a doublet ?

A. $\frac{1}{6}$

B. $\frac{1}{4}$

C. $\frac{2}{3}$

D. $\frac{3}{7}$

Solution:

In a simultaneous throw of dice, n (S) = (6 × 6) = 36
Let E = event of getting a doublet
= [(1, 1), (2, 2), (3, 3), (4, 4), (5, 5), (6, 6)]
∴ P(E) =

\frac{n (E)}{n (S)}

\frac{6}{36}

\frac{1}{6}

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