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1. In a single throw of die, what is the probability of getting a number greater than 4 ?

A. $\frac{1}{2}$

B. $\frac{1}{3}$

C. $\frac{2}{3}$

D. $\frac{1}{4}$

Solution:

When a die is thrown, we have S = {1, 2, 3, 4, 5, 6}
Let, E = event of getting a number greater than 4 = {5, 6}

∴ P (E) = \frac{n (E)}{n (S)} = \frac{2}{6} = \frac{1}{3}

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