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1. $\frac{\log \sqrt{8}}{\log 8}$ is equal to:

A. $\frac{1}{6}$

B. $\frac{1}{4}$

C. $\frac{1}{2}$

D. $\frac{1}{8}$

Solution:

\begin{aligned} \frac{\log \sqrt{8}}{\log 8} = {\frac{\log (8)}{\log 8}}^{\frac{1}{2}} \\ = \frac{\frac{1}{2} \log 8}{\log 8} \\ = \frac{1}{2} \end{aligned}

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