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1. $If 1 0^{x} = \frac{1}{2} then 1 0^{- 8 x} = ?$

A. $\frac{1}{256}$

B. 16

C. 80

D. 256

Solution:

\begin{aligned} 1 0^{- 8 x} \\ = {[10^{x}]}^{- 8} \\ = {[\frac{1}{2}]}^{- 8} \\ = 2^{8} \\ = 256 \end{aligned}

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