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1. Reduce $\frac{128352}{238368}$ to its lowest terms.

A. $\frac{3}{4}$

B. $\frac{5}{13}$

C. $\frac{7}{13}$

D. $\frac{9}{13}$

Solution:

\begin{aligned} 128352 \bar{) 238368 (} 1 \\ 128352 \\ \bar{110016)128352(} 1 \\ 110016 \\ \bar{183336)110016(} 6 \\ \frac{110016}{\times} \\ So, H .C .F of 128352 and 238368 \\ =  18336 \\ ∴ \frac{128352}{238368} = \frac{128352 \div 18336}{238368 \div 18336} = \frac{7}{13} \end{aligned}

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