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1. The average of first five multiples of 3 is:

A. 9

B. 10

C. 8

D. 11

Solution:

First five multiples of three are:
3, 6, 9, 12, 15.

\begin{aligned} Average = \frac{3 + 6 + 9 + 12 + 15}{5} \\ = \frac{45}{5} \\ = 9 \end{aligned}

Alternatively,
Average =

\frac{3 + 15}{2} = 9

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