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1. The average of the first five multiples of 9 is:

A. 20

B. 27

C. 28

D. 30

Solution:

\begin{aligned} Required average \\ = \frac{total sum of multiple of 9}{5} \\ = \frac{9 + 18 + 27 + 36 + 45}{5} \\ = 27 \end{aligned}

Note that, average of 9 and 45 is also 27.
And average of 18 and 36 is also 27.

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