Home > Practice > Arithmetic Aptitude > Average > Miscellaneous
1. The average wages of a worker during a fortnight comprising 15 consecutive working days was Rs.90 per day. During the first 7 days, his average wages was Rs.87/day and the average wages during the last 7 days was Rs.92 /day. What was his wage on the 8th day?
= 15 × 90
= Rs. 1350
The total wages earned during the first 7 days
= 7 × 87
= Rs. 609
The total wages earned during the last 7 days
= 7 × 92
= Rs. 644
Total wages earned during the 15 days,
= wages during first 7 days + wage on 8th day + wages during the last 7 days.
1350 = 609 + wage on 8th day + 644
wage on 8th day = 1350 - 609 - 644 = Rs. 97
Solution:
The total wages earned during the 15 days that the worker worked ,= 15 × 90
= Rs. 1350
The total wages earned during the first 7 days
= 7 × 87
= Rs. 609
The total wages earned during the last 7 days
= 7 × 92
= Rs. 644
Total wages earned during the 15 days,
= wages during first 7 days + wage on 8th day + wages during the last 7 days.
1350 = 609 + wage on 8th day + 644
wage on 8th day = 1350 - 609 - 644 = Rs. 97