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1. The base of triangle is 15 cm and height is 12 cm the height of another triangle of double the area having base 20 cm is :

A. 22 cm

B. 20 cm

C. 18 cm

D. 10 cm

Solution:

Given base of triangle and its height is 15 cm and 12 cm respectively
Area of first triangle :

\begin{aligned} = \frac{1}{2} \times Base \times Height \\ = \frac{1}{2} \times 15 \times 12 \\ = 90 sq . cm \end{aligned}

According to the question,
Let height of triangle be h cm
Area of new triangle = 180 sq. cm
Base = 20 sq. cm

\begin{aligned} \Rightarrow 180 = \frac{1}{2} \times 20 \times Height \\ \Rightarrow h = \frac{2 \times 180}{20} \\ \Rightarrow h = 18 cm \end{aligned}

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