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1. The H.C.F. of $\frac{9}{10},$ $\frac{12}{25},$ $\frac{18}{35}$ and $\frac{21}{40}$ is:

A. $\frac{3}{5}$

B. $\frac{252}{5}$

C. $\frac{3}{1400}$

D. $\frac{63}{700}$

Solution:

\begin{aligned} Required H .C .F . \\ = \frac{H .C .F . of 9, 12, 18, 21}{L .C .M . of 10, 25, 35, 40} \\ = \frac{3}{1400} \end{aligned}

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