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1. The HCF of $\frac{9}{10}, \frac{12}{25}, \frac{18}{35}$ and $\frac{21}{40}$ is = ?

A. $\frac{3}{5}$

B. $\frac{252}{5}$

C. $\frac{3}{1400}$

D. $\frac{63}{700}$

Solution:

\begin{aligned} Required HCF \\ = \frac{HCF of 9,12,18,21}{LCM of 10,25,35,40} \\ = \frac{3}{1400} \end{aligned}

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