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1. The LCM of two numbers is 12 times their HCF. The sum of HCF and LCM is 403. If one number is 93, find the other = ?

Solution:
Let HCF be h and LCM be lThen l= 12h and l+h = 40312h+h=403 or h= 31So l = (40331)=372Hence other number = (31×37293)=124

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