Home > Practice > Arithmetic Aptitude > HCF & LCM of Numbers > Miscellaneous
1. The least number which when divided by 4, 6, 8, 12 and 16 leaves remainder of 2 in each case is = ?

Solution:
LCM of (4, 6, 8, 12, 16)
⇒ 16 × 3 = 48
∴ The number when divided by (4, 6, 8, 12, 16) leaves remainder 2 is
= 48 + 2
= 50

You must login to add comments. Login now.