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1. The least number which when divided by 4, 6, 8 and 9 leave zero remainder in each case and when divided by 13 leaves a remainder of 7 is = ?

Solution:
LCM of (4, 6, 8, 9)
= 2 × 2 × 3 × 2 × 3
= 72
∴ Required result should be = 72

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