Practice | Hashtable

1. The length of the longest rod that can be placed in a room of dimensions 10 m × 10 m × 5 m is :

A. 15 $\sqrt{3}$ m

B. 15 m

C. 10 $\sqrt{2}$ m

D. 5 $\sqrt{3}$ m

Solution:

Required length :

\begin{aligned} = \sqrt{{(10)}^{2} + {(10)}^{2} + {(5)}^{2}} m \\ = \sqrt{225} m \\ = 15 m \end{aligned}

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