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1. The number nearest to 10000, which is exactly divisible by each of 3, 4, 5, 6, 7 and 8 is = ?
⇒ divided 10000 by LCM
⇒ we get remainder = 760
Now two possibilities are
= 10000 - 760 = 9240
or 10000 + (840 - 760) = 10080
So, nearest number is = 10080
Solution:
LCM of (3, 4, 5, 6, 7, 8) = 3 × 4 × 5 × 7 × 2 = 840⇒ divided 10000 by LCM
⇒ we get remainder = 760
Now two possibilities are
= 10000 - 760 = 9240
or 10000 + (840 - 760) = 10080
So, nearest number is = 10080