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1. The perimeter of a rectangle is 60 metres. If its length is twice its breadth, then its area is :
Then, length of the rectangle = 2x metres
⇒ 2(2x + x) = 60
⇒ 6x = 60
⇒ x = 10
So, length = 20 m, breadth = 10 m
∴ Area = (20 × 10) m2 = 200 m2
Solution:
Let the breadth of the rectangle be x metresThen, length of the rectangle = 2x metres
⇒ 2(2x + x) = 60
⇒ 6x = 60
⇒ x = 10
So, length = 20 m, breadth = 10 m
∴ Area = (20 × 10) m2 = 200 m2