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1. The present ages of three persons in proportions 4 : 7 : 9. Eight years ago, the sum of their ages was 56. Find their present ages (in years).
Then, (4x - 8) + (7x - 8) + (9x - 8) = 56
⇒ 20x = 80
⇒ x = 4
∴ Their present ages are 4x = 16 years, 7x = 28 years and 9x = 36 years respectively.
Solution:
Let their present ages be 4x, 7x and 9x years respectively.Then, (4x - 8) + (7x - 8) + (9x - 8) = 56
⇒ 20x = 80
⇒ x = 4
∴ Their present ages are 4x = 16 years, 7x = 28 years and 9x = 36 years respectively.